Final answer:
The voltage drop (ΔV) across a 1.0 MΩ resistor when 2.0 A of current passes through is calculated using Ohm's law (V = IR) to be 2,000,000 volts or 2 MegaVolts (MV).
Step-by-step explanation:
When 2.0 A of current moves across a 1.0 MΩ resistor, we can calculate the drop in voltage (ΔV) across the resistor using Ohm's law, which is stated as V = IR, where V is the voltage, I is the current, and R is the resistance. Here, the current I = 2.0 A and the resistance R = 1.0 MΩ, which is equivalent to 1,000,000 Ω. So, the voltage drop across the resistor can be calculated as follows:
ΔV = I × R
ΔV = 2.0 A × 1,000,000 Ω
ΔV = 2,000,000 V
Therefore, the voltage drop across the 1.0 MΩ resistor when 2.0 A of current passes through is 2,000,000 volts or 2 MegaVolts (MV).