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How many Grams of ribose (a carbohydrate) must be added to

200 mL of water to prepare a O.IM ribose solution?

User CaptureWiz
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1 Answer

16 votes
16 votes

Answer:

3 grams C₅H₁₀O₅

Step-by-step explanation:

To find the mass of ribose needed to prepare the sample, you need to

(1) convert the volume from mL to L (1,000 mL = 1 L)

(2) calculate the number of moles (M = moles / L)

(3) convert moles to grams (using the molar mass of ribose)

The molecular formula of ribose is C₅H₁₀O₅. It is important to arrange all of the ratios/conversions in a way that allows for the cancellation of units.

(Step 1)

200 mL C₅H₁₀O₅ 1 L
---------------------------- x ---------------------- = 0.2 L C₅H₁₀O₅
1,000 mL

(Step 2)

Molarity (M) = moles / volume (L) <----- Molarity ratio

0.1 M = moles / 0.2 L <----- Insert values

0.02 = moles <----- Multiply both sides by 0.2 L

(Step 3)

Atomic Mass (C): 12.011 g/mol

Atomic Mass (H): 1.008 g/mol

Atomic Mass (O): 15.999 g/mol

Molar Mass (C₅H₁₀O₅): 5(12.011 g/mol) + 10(1.008 g/mol) + 5(15.999 g/mol) = 150.13 g/mol

0.02 moles C₅H₁₀O₅ 150.13 g
---------------------------------- x ------------------- = 3 grams C₅H₁₀O₅
1 mole

User Daniel Egan
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