Question

A line has a slope of 1 and passes through the point (-2, 8). What is its equation in slope-intercept form?

Answer 1

Answer: The answer is y=x+10

Answer 2

`(\stackrel{x_1}{-2}~,~\stackrel{y_1}{8})\hspace{10em} \stackrel{slope}{m} ~=~ 1 \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{ 1}(x-\stackrel{x_1}{(-2)}) \implies y -8= 1 (x +2) \\\\\\ y-8=x+2\implies {\Large \begin{array}{llll} y=x+10 \end{array}}`