Question

Earth’s gravitational field is 7.51 N/kg at the altitude of the space shuttle. What is the size of the force of attraction between a student of mass 53 kg and Earth? Answer in units of N.

Answer 1

Step-by-step explanation:

395.53 N

The force of attraction between a student of mass 53 kg and Earth is calculated using the equation F = G*m1*m2/r^2, where G is the gravitational constant (7.51 N/kg), m1 is the mass of the student (53 kg), m2 is the mass of Earth, and r is the distance between them (the altitude of the space shuttle). Plugging in these values, we get F = 7.51*53*5.97e24/((6.37e6 + 6.37e6)^2) = 395.53 N.