Final answer:
A C++ low pass filter is implemented using a given formula without vectors. The code snippet defines a function to apply the filter and demonstrates its use in the main function. The smoothing factor, current input, and previous filtered value are used to calculate the filtered value.
Step-by-step explanation:
The question involves creating a simple low pass filter in C++ without utilizing vectors. To implement this filter, you'll be using the following formula: Yi = αxi + (1 − α)yi−1, where Yi is the filtered value, α is the smoothing factor, xi is the current input value, and yi−1 is the previous filtered value. Here's how you could implement this in C++:#include double lowPassFilter(double input, double prevFiltered, double alpha) { return alpha * input + (1 - alpha) * prevFiltered;}int main() { double alpha = 0.5; // smoothing factor double filteredValue = 0; // initial filtered value double inputValue; // Simulation of receiving input values while (std::cin >> inputValue) { filteredValue =lowPassFilter(inputValue,filteredValue, alpha); std::cout << "Filtered Value: " << filteredValue << std::endl; } return 0;}
This code defines a lowPassFilter function which applies the filter to the input value. In the main function, we simulate receiving input values, apply the filter, and output the results.A low-pass filter is a signal processing filter that allows low-frequency signals to pass through while attenuating higher-frequency signals. In this case, the low pass filter is based on a state equation and implemented without using vectors in C++.The formula for the low-pass filter is Yi = αxi + (1 − α)yi−1, where Yi is the filtered output, xi is the input signal, yi-1 is the previous filtered output, and α is a coefficient that determines the amount of emphasis given to the current input signal.Example:If α is set to 0.5, it means the output value is a combination of half of the current input value and half of theprevious filtered output value. This allows the filter to smoothen out the input signal and reduce high-frequency noise.