Question

Design the pseudocode to print a binary tree. At the visit of a node of the tree, it prints the node based on its (x, y) coordinates where x = the inorder rank of the node and y = depth of the node in the tree. Your algorithm time complexity must be linear in n, i.e., the tight bound on time complexity must be O(n), where n is the number of nodes.

Answer 1

To print a binary tree, use an inorder traversal algorithm. The pseudocode visits each node and prints it with its (x, y) coordinates. The time complexity of the algorithm is O(n).

Step-by-step explanation:

To print a binary tree using pseudocode, we can use an inorder traversal algorithm. Here is an example of how the pseudocode can look:

procedure printBinaryTree(node, x, y):
if node is not null:
printBinaryTree(node.leftChild, x - 1, y + 1) // traverse left child
print node.value + " (" + x + "," + y + ")" // print node and its coordinates
printBinaryTree(node.rightChild, x + 1, y + 1) // traverse right child
// Starting point of the algorithm:
root = getRootOfBinaryTree()
printBinaryTree(root, 0, 0)In this pseudocode, the 'printBinaryTree' procedure takes in a 'node' parameter, as well as the 'x' and 'y' coordinates. It recursively traverses the binary tree in the inorder fashion and prints each node along with its coordinates. The time complexity of this algorithm is O(n), where n is the number of nodes in the binary tree.