Final answer:
The rocket will be 16 feet above the ground at t = 1 sec and t = 2 sec.
Step-by-step explanation:
To find the time when the rocket will be 16 feet above the ground, we set the height function h(t) to 16 and solve for t:
16 = -16t^2 + 32t
Re-arranging the equation, we get:
-16t^2 + 32t - 16 = 0
Using the quadratic formula, the solutions for t are:
t = 1 sec and t = 2 sec
Therefore, the rocket will be 16 feet above the ground at t = 1 sec and t = 2 sec.