Question

Consider the following sets:

A = (⁄0 < ≤ 8; ∈ ), B = (1, 2, 3, 4), C = (3, 4, 5, 6), D = (2, 3, 6, 7). Determine:
a) The complement of set A (N(A))
b) The complement of set B (N(B))
c) The complement of set C (N(C))

Answer 1

The complement of set A (N(A)) is {9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19}. The complement of set B (N(B)) is {5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19}. The complement of set C (N(C)) is {1, 2, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19}.

Step-by-step explanation:

a) The complement of set A (N(A)) is the set of all outcomes that are not in A. In this case, A = {1, 2, 3, 4, 5, 6, 7, 8}, so its complement N(A) would be all the numbers outside this set, which is N(A) = {9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19}.

b) The complement of set B (N(B)) is the set of all outcomes that are not in B. In this case, B = {1, 2, 3, 4}, so its complement N(B) would be all the numbers outside this set, which is N(B) = {5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19}.

c) The complement of set C (N(C)) is the set of all outcomes that are not in C. In this case, C = {3, 4, 5, 6}, so its complement N(C) would be all the numbers outside this set, which is N(C) = {1, 2, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19}.