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What is the derivative of ( s = -2.1t^3 + 70.8t^2 - 777.1t + 2893.6 )? Then find the instantaneous rate of change at ( t = 9 ) corresponding to the years 2010 and 2012.

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Final answer:

The derivative of the function is -6.3t^2 + 141.6t - 777.1. The instantaneous rate of change at t = 9 is -13.

Step-by-step explanation:

To find the derivative of the given function, we need to take the derivative of each term separately. The derivative of -2.1t^3 is -6.3t^2, the derivative of 70.8t^2 is 141.6t, the derivative of -777.1t is -777.1, and the derivative of 2893.6 is 0. Therefore, the derivative of the function is -6.3t^2 + 141.6t - 777.1.

To find the instantaneous rate of change at t = 9, we evaluate the derivative at t = 9. Substituting t = 9 into the derivative function, we have (-6.3(9^2) + 141.6(9) - 777.1) = (-510.3 + 1274.4 - 777.1) = -13.

The instantaneous rate of change at t = 9 is -13.

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