Final answer:
To calculate the mass of H2 that will be produced when 122 g of Zn are reacted, you can use stoichiometry. The mass of H2 produced will be equal to the mass of Zn since the stoichiometry of the reaction is 1:1.
Step-by-step explanation:
To calculate the mass of H2 that will be produced when 122 g of Zn are reacted, we need to use stoichiometry. The balanced equation for the reaction is:
Zn + 2HCl → ZnCl2 + H2
From the equation, we can see that for every 1 mole of Zn, 1 mole of H2 is produced. The molar mass of Zn is 65.38 g/mol, so we can calculate the number of moles of Zn:
Number of moles of Zn = mass of Zn / molar mass of Zn = 122 g / 65.38 g/mol = 1.864 mol
Since the stoichiometry of the reaction is 1:1, the mass of H2 produced will be equal to the mass of Zn. Therefore, the mass of H2 produced when 122 g of Zn are reacted is 122 g.