Question

A force of 850-1b is applied to a nickel wire with a 0.15-in. diameter. The wire has a yield strength of 45,000 psi and a tensile strength of 55,000 psi. Will the wire plastically deform if subjected to a strain of E-0.005?

a) Yes
b) No

Answer 1

To determine if the wire will plastically deform, we can calculate the stress applied to the wire and compare it to its yield strength. If the stress is greater than the yield strength, the wire will deform.

Step-by-step explanation:

To determine if the wire will plastically deform, we can calculate the stress applied to the wire and compare it to its yield strength. The stress can be calculated using the formula:

Stress = Force / Area

The area of the wire can be calculated using the formula for the area of a circle:

Area = π * (diameter/2)^2

Plugging in the given values, we get:

Stress = 850 lb / (π * (0.15/2)^2 in^2)

Now we can calculate the stress in psi by converting the units:

1 lb/in^2 = 0.000145 ksi

Stress (psi) = Stress (lb/in^2) * 0.000145 ksi

Finally, we can compare the stress to the yield strength of the wire to determine if it will plastically deform. If the stress is greater than the yield strength, the wire will deform:

If Stress >= Yield Strength: Wire will plastically deform (a) Yes

If Stress < Yield Strength: Wire will not plastically deform (b) No