Question

What values of y would make the following equation true?

y² - 6y - 11 = 0

A. 5+2 13
B. 6+22
C. 2+3/15
D. 3+2.5

Answer 1

To find the values of y that make the equation y² - 6y - 11 = 0 true, we can solve the quadratic equation by factoring.

Step-by-step explanation:

To find the values of y that would make the equation y² - 6y - 11 = 0 true, we need to solve the equation.

We can solve this quadratic equation by factoring, completing the square, or using the quadratic formula. In this case, factoring is the most efficient method.

Factoring the equation, we get (y - 11)(y + 1) = 0.

This equation is true when either y - 11 = 0 or y + 1 = 0. Solving these equations, we find that the values of y that make the equation true are y = 11 and y = -1.