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Calculate the concentration of tartrate ion (C₄​H₄​O₆²⁻​) in a 0.175 M solution of tartaric acid (H₂​C₄​H₄​O₆​). For tartaric acid, Ka1​=1.0×10⁻³ and Ka₂​​=4.6×10⁻⁵.

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Final answer:

To calculate the concentration of tartrate ion (C₄​H₄​O₆²⁻​) in a 0.175 M solution of tartaric acid (H₂​C₄​H₄​O₆​), you can use the dissociation of tartaric acid into its ions and the acid dissociation constant (Ka).

Step-by-step explanation:

To calculate the concentration of tartrate ion (C₄​H₄​O₆²⁻) in a 0.175 M solution of tartaric acid (H₂​C₄​H₄​O₆​), we need to consider the dissociation of tartaric acid into its ions. Tartaric acid is a diprotic acid, so it can lose two hydrogen ions in a stepwise manner.

The dissociation of tartaric acid can be represented by the following equations:

H₂C₄​H₄​O₆​​ → H⁺ + HC₄​H₄​O₆⁻​

HC₄​H₄​O₆⁻​ → H⁺ + C₄​H₄​O₆²⁻

The concentration of tartrate ion (C₄​H₄​O₆²⁻​) is equal to the concentration of HC₄​H₄​O₆⁻​, which is the ion produced in the second dissociation step. The acid dissociation constant (Ka) for the second dissociation step is given as Ka₂​​= 4.6×10⁻⁵.

So, we can use the value of Ka₂​​ and the initial concentration of tartaric acid (0.175 M) to calculate the concentration of tartrate ion. This can be done using an ICE table and the expression for Ka. The final concentration of tartrate ion can be calculated as [C₄​H₄​O₆²⁻​] = Ka₂​​ × [HC₄​H₄​O₆⁻​].

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