Final answer:
To determine if the stimulant increases the mean concentration score by more than 10 points, we will conduct a hypothesis test. We'll use a one-tailed t-test with a significance level of 0.01. Using the given data, you should be able to perform the calculations and determine the results.
Step-by-step explanation:
To determine if there is evidence to suggest that the stimulant increases the mean concentration score by more than 10 points, we will conduct a hypothesis test. Let's denote the mean concentration score for the stimulant group as μstimulant and the mean concentration score for the control group as μcontrol. We'll use a one-tailed t-test with a significance level of α = 0.01.
Null Hypothesis (H0): μstimulant - μcontrol ≤ 10
Alternative Hypothesis (Ha): μstimulant - μcontrol > 10
We'll calculate the t-statistic using the formula: t = (μstimulant - μcontrol) / sqrt(sstimulant2/nstimulant + scontrol2/ncontrol), where sstimulant is the standard deviation of the stimulant group's scores, scontrol is the standard deviation of the control group's scores, nstimulant is the number of participants in the stimulant group, and ncontrol is the number of participants in the control group.
We'll compare the t-statistic to the critical value from the t-distribution table with (nstimulant + ncontrol - 2) degrees of freedom and the given significance level. If the t-statistic is greater than the critical value, we'll reject the null hypothesis. Otherwise, we'll fail to reject the null hypothesis.
Using the given data, you should be able to perform the calculations and determine if there is evidence to suggest that the stimulant increases the mean concentration score by more than 10 points.