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How many liters of a 7.0 % ( m/v ) glucose solution would you need to obtain 90 g of glucose?

User Gokhan
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Final answer:

To obtain 90 g of glucose from a 7.0% (m/v) glucose solution, you would need 1.28571 liters of the solution.

Step-by-step explanation:

To calculate how many liters of a 7.0% (m/v) glucose solution are needed to obtain 90 g of glucose, you would use the formula:

Mass = Volume × Concentration (m/v)

From the formula, the Volume can be isolated as follows:

Volume = Mass / Concentration

For a 7.0% (m/v) solution, this means that there are 7.0 g of glucose in every 100 mL of solution. To find out how many milliliters are needed for 90 g:

Volume = 90 g / (7.0 g/100 mL) = 1285.71 mL

To convert this to liters:

Volume in liters = 1285.71 mL / 1000 mL/L = 1.28571 L

Therefore, 1.28571 liters of a 7.0% (m/v) glucose solution are required to obtain 90 g of glucose.

User Cherisse
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