Question

I am a three-digit number; the digit on my tens place value is 6 more than the digit on the place value of ones. The digit on my hundreds place value is 8 less than the tens digit. What number am I?

Answer 1

The student's question is a math problem involving place values where each place is related to the others by a specific numeric difference. By analyzing the relationships, we can figure out that the three-digit number is 193.

Step-by-step explanation:

The student's question involves identifying a three-digit number based on given place value relationships. Specifically, we are told that the tens place is 6 more than the ones place, and the hundreds place is 8 less than the tens place. We can set up the following relationships between the digits of the number, where 'O' stands for ones, 'T' for tens, and 'H' for hundreds:

T = O + 6

H = T - 8

Because T is 6 more than O and digits can only be 0-9, the highest value for O is 3, which would make T = 9 (since 3 + 6 = 9). With T as 9, we can then determine H by subtracting 8 from T, giving us H = 1 (since 9 - 8 = 1). The number is therefore 193.