187k views
4 votes
Expand the expression: ln(3x^2y).

User Ahti Ahde
by
7.8k points

1 Answer

2 votes

Final answer:

To expand the expression ln(3x^2y), use logarithmic properties to separate the product and exponent terms, resulting in ln(3) + 2*ln(x) + ln(y).

Step-by-step explanation:

To expand the expression ln(3x^2y), we will apply logarithmic properties that help simplify the expression. The properties we will use are:

  • The logarithm of a product of two numbers is the sum of the logarithms of those two numbers: ln(xy) = ln(x) + ln(y).
  • The logarithm of a number raised to an exponent is the product of the exponent and the logarithm of the number: ln(x^n) = n * ln(x).

Using these properties, we can expand ln(3x^2y) into simpler terms:

  1. Apply the first property to separate the terms: ln(3) + ln(x^2y).
  2. Separate x^2 and y using the first property again: ln(3) + ln(x^2) + ln(y).
  3. Apply the second property to the term x^2: ln(3) + 2*ln(x) + ln(y).

Therefore, the expanded form of ln(3x^2y) is ln(3) + 2*ln(x) + ln(y).

User KillerX
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories