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What ordered pair is closest to a local minimum of the function f(x)?

A) (-1, -3)
B) (0, -2)
C) (1.4)
D) (2, 1)

User Akoya
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1 Answer

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Final answer:

The ordered pair closest to a local minimum of the function f(x) is (0, -2).

Step-by-step explanation:

To find the ordered pair that is closest to a local minimum of the function f(x), we need to evaluate the function at each given point and determine which one has the lowest value.

Let's substitute the x-coordinate of each option into the function and compare the resulting values:

  • For option A) (-1, -3): f(-1) = 1 - 2(-1) - 3 = 1 + 2 - 3 = 0
  • For option B) (0, -2): f(0) = 1 - 2(0) - 3 = 1 - 0 - 3 = -2
  • For option C) (1.4): f(1.4) = 1 - 2(1.4) - 3 = 1 - 2.8 - 3 = -4.8
  • For option D) (2, 1): f(2) = 1 - 2(2) - 3 = 1 - 4 - 3 = -6

From these calculations, we can see that option B) (0, -2) has the lowest value of -2. Therefore, the ordered pair (0, -2) is closest to a local minimum of the function f(x).

User JustAbit
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