Question

What amount of sodium ions in mmol does 50 ml sodium chloride solution 0.9% w/v (normal saline) intravenous infusion contain? There are 150 mmol each of Na+ and Cl- / L of NaCl 0.9% w/v IV infusion.

A. 3.75 mmol
B. 7.50 mmol
C. 11.25 mmol
D. 15.00 mmol

Answer 1

The 50 ml sodium chloride solution 0.9% w/v (normal saline) intravenous infusion contains 0.073 mmol of sodium ions.

Step-by-step explanation:

To determine the amount of sodium ions in a 50 ml sodium chloride solution 0.9% w/v (normal saline), we need to calculate the number of moles of sodium ions present in the solution and then convert it to millimoles (mmol).

First, we start by calculating the number of moles of sodium chloride in the solution:

Concentration of NaCl in the solution = 0.9% w/v = 0.9 g / 100 ml

Mass of NaCl in 50 ml solution = (0.9 g / 100 ml) x 50 ml = 0.45 g

Moles of NaCl = Mass / molar mass = 0.45 g / (22.99 g/mol + 35.45 g/mol) = 0.0097 mol

Since there are 150 mmol each of Na+ and Cl- in 1 L of NaCl 0.9% w/v IV infusion, the number of mmol of Na+ in 50 ml solution is:

mmol Na+ = (0.0097 mol / 1 L) x (150 mmol / 1000 ml) x 50 ml = 0.073 mmol

Therefore, the 50 ml sodium chloride solution 0.9% w/v (normal saline) intravenous infusion contains 0.073 mmol of sodium ions.