206k views
4 votes
A start-up owner is looking to meet new investors to get some funds for his company. Each investor has a tight schedule that the owner has to respect. Given the schedules of the days investors are available, determine how many meetings the owner can schedule. Note that the owner can only have one meeting per day. The schedules consist of two integer arrays, firstDay and lastDay. Each element in the array firstArray represents the first day an investor is available, and each element in lastDay represents the last day an investor is available, both inclusive. How do we write this in a Java program?

a) Implement a loop to iterate through the arrays and count overlapping days
b) Use recursion to find the optimal schedule for the owner
c) Utilize a hashmap to store available days for each investor
d) Apply a binary search algorithm to optimize the meeting schedule.

User Stiegi
by
7.4k points

1 Answer

3 votes

Final answer:

The problem is to write a Java program to maximize the number of investor meetings using provided arrays of availability. A greedy algorithm, sorting by end dates and choosing the earliest non-conflicting meeting seems most effective among the given choices. Detailed coding is beyond the response scope.

Step-by-step explanation:

The question involves solving a practical problem through programming, a skill typically covered within a Computers and Technology course at the College level. The task presented is to write a Java program that maximizes the number of investor meetings for a start-up owner based on arrays indicating investors' availability. To achieve this, one would typically create a function that takes in two arrays, firstDay and lastDay, representing the start and end of investor availability, respectively. From the options provided:

  • Implementing a loop to iterate through the arrays and count overlapping days is a straightforward method to identify potential meeting days but doesn't guarantee the maximization of meetings.
  • Recursion could be used, but it may not be the most efficient choice for this type of problem.
  • Using a hashmap could help to store and quickly access the availability of each investor, but managing overlaps would still require additional logic.
  • Applying a binary search algorithm would not be appropriate as it's typically used for searching, not scheduling or optimization purposes.

Therefore, the best approach is likely a form of greedy algorithm that always schedules the earliest possible meeting while maintaining a count of total meetings. An algorithm that sorts investors by their last available day first and then iteratively schedules the earliest meeting that doesn't conflict with previously scheduled ones would work efficiently. However, writing such a program would require detailed coding which is beyond the scope of this platform's response capabilities.

User Aholt
by
8.1k points