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If a container of water absorbs (3.4 ,cal) of heat, what is the amount of energy absorbed (in joules)?

a) (14.2 ,J)
b) (18.4 ,J)
c) (142 ,J)
d) (68.6 ,J)

User Sheff
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1 Answer

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Final answer:

To convert the energy absorbed by water from calories to joules, multiply the given energy in calories (3.4 cal) by the conversion factor 4.184 J/cal, resulting in 14.2 J.

Step-by-step explanation:

When a container of water absorbs 3.4 calories (cal) of heat, we can convert this energy to joules (J) using the conversion factor that 1 calorie is approximately equal to 4.184 joules. The calculation is as follows:

Energy absorbed in joules = 3.4 cal × 4.184 J/cal = 14.2256 J.

When rounded to the nearest tenth, the energy absorbed is 14.2 J, which corresponds to answer option (a).

The amount of energy absorbed (in joules) is 2.67 × 10^7 J or 2.67 × 10^4 kJ.

The specific heat of water is 4.184 J/(g•°C), and the temperature change is 16.0°C. Using the equation q=mc∆T, where q is the heat absorbed, m is the mass of water, and ∆T is the temperature change, we can calculate the amount of energy absorbed by the water.

Plugging in the values, we get q = (3.99 × 10^3 g) (16.0°C) = 2.67 × 10^7 J = 2.67 × 10^4 kJ.

User Markus Mitterauer
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