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I am trying to find the relation between emissivity of a material, viewing angle(from normal) and temperature of a grey body. Is there a formula that gives us this relation? This is to create an emissivity map of a silicon wafer that is viewed from a certain angle and which is at a certain temperature.

User Kamcknig
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Final answer:

The relationship between emissivity, viewing angle, and temperature of a grey body can be described using the Stefan-Boltzmann law. The formula to calculate the radiated power is P = σ * A * e * T^4, where P is the power emitted, σ is the Stefan-Boltzmann constant, A is the surface area, e is the emissivity, and T is the temperature in Kelvin.

Step-by-step explanation:

The relationship between the emissivity of a material, the viewing angle (from normal), and the temperature of a grey body can be described using the Stefan-Boltzmann law. The Stefan-Boltzmann law states that the amount of radiation emitted by a blackbody is proportional to its emissivity, surface area, and the fourth power of its temperature.

So, the formula to calculate the radiated power is:

P = σ * A * e * T^4

Where P is the power emitted, σ is the Stefan-Boltzmann constant (5.67 × 10^-8 J/s · m² · K^4), A is the surface area of the object, e is the emissivity of the material, and T is the absolute temperature in Kelvin.

User Gerardo Roza
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