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Why is the preparation of alkynes by dehydrohalogenation often carried out in two steps?

a) Sodamide acts as a base deprotonating the dihalide
b) Sodamide acts as a nucleophile displacing halides
c) To control the reaction and prevent runaway polymerization
d) All of the above

User Lebhero
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Final answer:

The dehydrohalogenation of alkyl halides to form alkynes is typically performed in two steps to achieve control over the reaction and prevent over-dehydrohalogenation or polymerization, ensuring the desired alkyne is obtained.

Step-by-step explanation:

The preparation of alkynes by dehydrohalogenation is often carried out in two steps to control the reaction and prevent further reactions such as runaway polymerization. This two-step process is not solely because sodamide acts as a base or nucleophile, although it does indeed act as a base in the deprotonating step. The reasons behind a two-step method include controlling the reaction to obtain a specific product and avoiding over-dehydrohalogenation which can lead to side reactions or polymerization. The stepwise approach allows for precise removal of hydrogen halides to achieve the alkyne compound without further unsought transformations.

User Matthew Kraus
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