Answer:
For number of units of hockey stick = 24
For number of units of chess sets = 4
Maximum possible profit = $64
Step-by-step explanation:
Decision Variables:
Number of units of Hockey sticks and chess sets
Number of Units Hockey Sticks Chess Sets
H C
Objective Function:
Maximize the total profit:
Max P = 2H + 4C
Constraints:
4H + 6C
120 hours ---> A
2H + 6C
72 hours ---->B
C
10 hours -----> C
H, C
0
For this question to solve, we need to draw a feasible region diagram, which I have attached in the attachment. Please refer to it.
So,
Points According to the feasible region are:
D(0,10) ; A(6,10) ; B(24,4) ; C(30,0) ;
Value of objective function at corner points:
At D(0,10) ; P = 2H + 4C = 2x0 + 4 x 10 = $40
At A(6,10); P = 2H + 4C = 2x6 + 4x10 = $52
At B((24,4) : P = 2H + 4C = 2 x 24 + 4x4 = $64
At C(30,0) ; P = 2H +4C = 2x30 + 4x0 = $60
Hence,
P is maximum at corner point B(24,4)
For number of units of hockey stick = 24
For number of units of chess sets = 4
Maximum possible profit = $64