Final answer:
The Feynman propagator Δ(0) is not defined in quantum field theory due to divergence at x = y. Regularization or renormalization techniques handle such infinities in calculations, and defining Δ(0) as 1 would be unconventional and not justified in the standard framework. The issue addresses challenges in QED faced by Nobel laureates Richard Feynman, Julian Schwinger, and S.I. Tomonaga.
Step-by-step explanation:
The question raises the issue of defining the Feynman propagator Δ(0) within the context of scalar field theory in Φ4 theory, particularly in Feynman diagram calculations. According to Peskin & Schroeder, the propagator is defined only for different times and diverges as x approaches y. The concept of amputation in Feynman diagrams refers to removing external lines and associated propagators that begin and end at the same vertex. Defining Δ(0) as 1 might seem a solution to ease the interpretation of particle movement, suggesting a unit probability of a particle remaining at the same point.
However, in quantum field theory, Δ(0) is usually not defined due to the divergence at x = y, and a regularization technique or renormalization is used to handle such infinities. Assigning a finite value like 1 to Δ(0) would be unconventional and not justified within the standard framework of quantum field theory. Instead, the role of such propagators is managed through regularization processes that ensure the physical observables remain finite and meaningful. Richard Feynman, Julian Schwinger, and S.I. Tomonaga's foundational work in quantum electrodynamics (QED) involved dealing with such infinities, which earned them the 1965 Nobel Prize.