436,322 views
22 votes
22 votes
Find the value of xxx in the isosceles triangle shown below.

Choose 1 answer:
Choose 1 answer:

(Choice A)
A
x = \sqrt{130}x=
130

x, equals, square root of, 130, end square root

(Choice B)
B
x = 12x=12x, equals, 12

(Choice C)
C
x = \sqrt{194}x=
194

x, equals, square root of, 194, end square root

(Choice D)
D
x = \sqrt{65}x=
65


User Daelan
by
2.8k points

2 Answers

11 votes
11 votes

Answer: (choice B) 12

Explanation:

In an isosceles triangle, two sides are equal in length. From the information given, the triangle has sides with lengths \(10\), \(13\), and \(13\), with a base of \(x\). Since it's isosceles, the two equal sides are \(13\) each, and the base is \(10\).

To find the value of \(x\), you can use the Pythagorean theorem. Let \(x\) be the height of the triangle, and then we have:

\[ x^2 + \left(\frac{10}{2}\right)^2 = 13^2 \]

\[ x^2 + 25 = 169 \]

\[ x^2 = 144 \]

\[ x = 12 \]

So, the correct answer is \(x = 12\), which matches Choice B.

Find the value of xxx in the isosceles triangle shown below. Choose 1 answer: Choose-example-1
User Adam Staszak
by
2.7k points
24 votes
24 votes

Answer:

Explanation:

bro this question is wrong needs more data

User Joe Sasson
by
3.2k points