Final answer:
The density of the woman who floats in freshwater with 4.00% of her volume above the surface is calculated at 960 kg/m³, considering freshwater density and the submerged volume of her body.
Step-by-step explanation:
The density of a woman who floats in freshwater with 4.00% of her volume above the surface can be determined by applying the principle of flotation, which states that a floating object displaces its own weight of the fluid it is in. Given that 4.00% of her volume is above the water, it means that 96.00% of her volume is submerged and displacing freshwater, which has a density of approximately 1000 kg/m³.
Therefore, since she is in equilibrium (floating) and not sinking, the density of the woman must be equal to the density of the water multiplied by the percentage of her volume that is submerged. This gives us:
Density of woman = Density of freshwater × (Percentage of volume submerged / 100)
Density of woman = 1000 kg/m³ × (96.00/100)
Density of woman = 960 kg/m³
The correct answer for the woman's density is A. rho = 960 kg/m³.