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What is the value of the equilibrium constant at 500 °C for the formation of NH3 according to the following equation?

a) [NH3]² / [N2][H2]³
b) [NH3] / [N2][H2]²
c) [NH3]³ / [N2][H2]²
d) [NH3]² / [N2][H2]

1 Answer

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Final answer:

The equilibrium constant expression for the formation of NH3 at 500 °C is given by [NH3]² / [N2][H2]³, reflecting the stoichiometry of the balanced chemical equation.

Step-by-step explanation:

The value of the equilibrium constant at 500 °C for the formation of NH3 according to the balanced chemical equation N2(g) + 3H2(g) → 2NH3(g) is represented by the expression [NH3]² / [N2][H2]³.

This is because the equilibrium constant expression (Kc or Kp) is defined by the concentrations of the products raised to the power of their coefficients divided by the concentrations of the reactants raised to the power of their coefficients.

In this case, for every one mole of N2 reacting, three moles of H2 react to form two moles of NH3, thus the powers in the equilibrium expression correspond to the coefficients according to the balanced reaction.

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