Question

Calculate the number of moles of HI that are at equilibrium with 1.25 mol of H2 and 1.25 mol of I2 in a 5.00−L flask at 448 °C.

a) 0.625
b) 1.25
c) 2.50
d) 5.00

Answer 1

The number of moles of HI at equilibrium with 1.25 mol of H2 and 1.25 mol of I2 in a 5.00-L flask at 448 °C is 1.25 mol.The correct answer is option B.

Step-by-step explanation:

To calculate the number of moles of HI at equilibrium, we need to determine the moles of H2 and I2 at equilibrium. Since the reaction is H2 + I2 → 2HI, we can use the stoichiometry of the reaction to find the moles of HI.

From the given information, we have 1.25 mol of H2 and 1.25 mol of I2. According to the balanced equation, for every 1 mole of H2, 1 mole of HI is produced. So, the moles of HI is equal to the moles of H2, which is 1.25 mol.

Therefore, the number of moles of HI at equilibrium with 1.25 mol of H2 and 1.25 mol of I2 is 1.25 mol.The correct answer is option B.