Final answer:
The molar solubility of BaSO₄ in a 0.250-M solution of NaHSO₄ is 1.05 × 10⁻⁵ M. All options are incorrect.
Step-by-step explanation:
To determine the molar solubility of BaSO₄ in a 0.250-M solution of NaHSO₄, we need to consider the common ion effect. NaHSO₄ dissociates into Na⁺ and HSO₄⁻ ions in solution. HSO₄⁻ is the common ion with BaSO₄, which can decrease the solubility of BaSO₄.
To calculate the molar solubility, we need to compare the initial concentration of BaSO₄ with its solubility product, Ksp. Since the concentration of BaSO₄ is unknown, we can assume it to be 'x'.
Using the Ksp expression for BaSO₄, we can write: Ksp = [Ba²⁺][SO₄²⁻] = (x)(x) = x²
The Ksp value for BaSO₄ is given as 1.1 × 10⁻¹⁰. Setting up the equation: x² = 1.1 × 10⁻¹⁰
Solving for x, we find the molar solubility of BaSO₄ to be x = 1.05 × 10⁻⁵ M
Hence, none of the options are correct.