Question

If 3.21 g of NH₄NO₃ in Example 5.6 were dissolved in 100.0 g of water under the same conditions, how much would the temperature change? Explain your answer.

a) −15.0°C
b) −7.5°C
c) 15.0°C
d) 7.5°C

Answer 1

To calculate the temperature change when 3.21 g of NH₄NO₃ is dissolved in 100.0 g of water, we can use the equation q = mCΔT.

However, the temperature change is not provided in the question, so we cannot determine the exact value.

Step-by-step explanation:

To calculate the temperature change when 3.21 g of NH₄NO₃ is dissolved in 100.0 g of water, we can use the equation:

q = mCΔT

Where q is the heat absorbed or released, m is the mass of the solution, C is the specific heat capacity of the solution, and ΔT is the change in temperature.

In this case, the mass of the solution is 100.0 g + 3.21 g = 103.21 g. Assuming the specific heat capacity of the solution is the same as that of water, which is 4.184 J/(g·°C), we can calculate the temperature change as follows:

q = (103.21 g)(4.184 J/(g·°C))ΔT

Given that the temperature change is not provided in the question, we cannot determine the exact value. Therefore, we cannot determine which option (a)−15.0°C, (b)−7.5°C, (c)15.0°C, or (d)7.5°C, is correct.