Final answer:
Lewis structures of C3H7ON isomers with an amide linkage include propionamide, ethanamide, and 2-propanol amide, which contain the proper groups and adhere to the molecular formula's atom counts.
Step-by-step explanation:
The student asked about writing the Lewis structures of all isomers with the formula C3H7ON that contain an amide linkage. An amide linkage involves a carbonyl group (C=O) attached to a nitrogen atom (N). The possible isomers of C3H7ON with an amide linkage are as follows:
Propionamide (CH3CONHCH2CH3): A linear amide where the amide group is on the terminal carbon.
Ethanamide (CH3CH2CONH2): Another linear amide but with the amide group at the second carbon.
2-Propanol amide (CH3CH(OH)CONH2): In this possible isomer, a hydroxyl and amide functionalities are present within the same molecule, with the amide at the terminal carbon and the hydroxyl on the middle carbon.
Each of these structures must have an amide linkage and should account for the total number of carbons (3), hydrogens (7), oxygen (1), and nitrogen (1) as specified in the molecular formula.