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A basketball player rises 1.25 m above the floor. What is the minimum velocity he must leave the ground with?

a) 11.2 m/s
b) 12.5 m/s
c) 13.6 m/s
d) 14.9 m/s

1 Answer

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Final answer:

To calculate the minimum velocity a basketball player must leave the ground with in order to rise 1.25 m above the floor, we can use the principles of projectile motion. The minimum velocity is 11.2 m/s.

Step-by-step explanation:

To calculate the minimum velocity a basketball player must leave the ground with in order to rise 1.25 m above the floor, we can use the principles of projectile motion. The vertical distance can be treated as the vertical displacement of a projectile, while the horizontal distance is not relevant in this case. We can use the equation:

vf^2 = vi^2 + 2ad

where vf is the final velocity, vi is the initial velocity, a is the acceleration (which is equal to -9.8 m/s^2 for upward motion), and d is the displacement (1.25 m in this case). By rearranging the equation and solving for vi, we find that the minimum velocity the basketball player must leave the ground with is 11.2 m/s (option a).

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