Question

Three parallel plates are stacked above each other, with a separation between each plate. If the potential difference between the first two plates is ΔV1 and the potential between the second two plates is ΔV2, what is the potential difference between the first and the third plates?

a) ΔV1 + ΔV2

b) ΔV1 - ΔV2

c) ΔV1 × ΔV2

d) ΔV1 / ΔV2

Answer 1

The potential difference between the first and third parallel plates is the sum of the potential differences between each pair of adjacent plates, which is ΔV1 + ΔV2.

Step-by-step explanation:

When considering three parallel plates with potential differences ΔV1 between the first and second plate, and ΔV2 between the second and third plate, the potential difference between the first and third plates is the sum of ΔV1 and ΔV2.

This is because potential differences in a circuit or between plates add up when they are in series. So, if you have ΔV1 between the first two plates and a ΔV2 between the second two plates, the total potential difference between the first and third plates would be ΔV1 + ΔV2.