Question

Differentiate the function y = -5e0 7log1

Answer 1

To differentiate the function y = -5e^0.7log(1), use the chain rule and differentiate the outer and inner functions separately before applying the chain rule to get the final derivative.

Step-by-step explanation:

To differentiate the function y = -5e^0.7log(1), we can use the chain rule. Let's break it down step-by-step:

1. First, differentiate the outer function: -5e^0.7log(1). The derivative of e^0.7log(1) is e^0.7log(1) multiplied by the derivative of 0.7log(1) which is 0.7.
2. Next, differentiate the inner function: log(1). The derivative of log(x) is 1/x. So the derivative of log(1) is 1/1 = 1.
3. Now, apply the chain rule: Multiply the derivative of the outer function (-5e^0.7log(1)) with the derivative of the inner function (1).

Putting it all together, the derivative of y = -5e^0.7log(1) is: -5e^0.7log(1) * 1 = -5e^0.7log(1).