Explanation:
remember that x^-n means 1/(x^n).
x^a × x^b = x^(a+b)
x^a / x^b = x^(a-b)
(x^a)^b = x^(a×b)
(x×y)^n = x^n × y^n
so,
a^2 / a^-2 = a^(2 - -2) = a^4
and
b^-3 / b^2 = b^(-3 - 2) = b^-5 = 1/(b^5)
that means we have then :
(a^4 × b^-5)^2 = (a^4)^2 × (b^-5)^2 = a^8 × b^-10 =
= a^8 / b^10 = a⁸/b¹⁰