Final Answer:
120 dB level is preceding.
The correct option is c) 120 dB.
Step-by-step explanation:
The sound intensity level (SIL) is given by the formula SIL = 10 * log10(I/I₀), where I is the sound intensity and I₀ is the reference intensity (usually taken as

In the context of the question, the sound intensity level is given as 120 dB. To find the corresponding sound intensity, we can rearrange the formula to solve for I:
![\[ 120 \, \text{dB} = 10 * \log_(10)(I/I₀) \]](https://img.qammunity.org/2024/formulas/physics/high-school/az8s0ieupr07r25nas1z4lxizcsxn3zde9.png)
Dividing both sides by 10:
![\[ 12 = \log_(10)(I/I₀) \]](https://img.qammunity.org/2024/formulas/physics/high-school/zj82gcwgjz20r6a0fauh61g4qhf6m5to31.png)
Now, raising both sides as powers of 10:
![\[ 10^(12) = I/I₀ \]](https://img.qammunity.org/2024/formulas/physics/high-school/gc4rf61uokyq77546rwsja68be3588osqi.png)
Multiplying both sides by I₀:
![\[ I = I₀ * 10^(12) \]](https://img.qammunity.org/2024/formulas/physics/high-school/jto3suqtzkfzisw1xa4l4p0zzxafukg6n4.png)
So, the sound intensity is
times the reference intensity. This corresponds to a sound intensity level of 120 dB.
Therefore, the correct answer is option c) 120 dB.