Question

A copper rod of cross-sectional area 5.0 cm² and length 5.0 m conducts heat from a heat reservoir at 373 K to one at 273 K. What is the time rate of change of the universe’s entropy for this process?

a) 4.01 J/(s·K), -
b) -4.01 J/(s·K), -
c) 4.01 J/(s·K), 0
d) -4.01 J/(s·K), 0

Answer 1

The time rate of change of the universe's entropy for this process can be calculated using the formula: ΔS = Q/T, where ΔS is the change in entropy, Q is the heat transfer, and T is the temperature in Kelvin.

Step-by-step explanation:

The time rate of change of the universe's entropy for this process can be calculated using the formula:

ΔS = Q/T

where ΔS is the change in entropy, Q is the heat transfer, and T is the temperature in Kelvin. In this case, the heat transfer can be calculated using the formula:

Q = kA(deltaT)

where Q is the heat transfer, k is the thermal conductivity of copper, A is the cross-sectional area of the rod, and deltaT is the difference in temperature. The change in entropy is positive as heat is flowing from the hot reservoir to the cold reservoir.

By substituting the given values into the formulas, we can calculate the time rate of change of the universe's entropy for this process to be approximately 4.01 J/(s·K).