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32 votes
How would you graph the equation y = (2/3)x+ 1 on the coordinate plane ​

How would you graph the equation y = (2/3)x+ 1 on the coordinate plane ​-example-1
User Jimmeh
by
3.2k points

1 Answer

12 votes
12 votes

Answer:

The graph has been attached. In the graph, These coordinates are plotted and a straight line passes through them.

Explanation:

Let's find the intercepts first

y intercept, (-3/2 , 0)

y=(2/3)x+1

(2/3)x+1=0

x=-3/2

X intercept, (0 , 1)

y=(2/3)x+1

=(2/3)×0+1

=1

coordinates, (-3/2 , 0) (0 , 1)

How would you graph the equation y = (2/3)x+ 1 on the coordinate plane ​-example-1
User Hooting
by
3.0k points
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