Question

A particle moves in a straight line with an initial velocity of 0 m/s and a constant acceleration of 30 m/s2. If x=0att=0, what is the particle’s position at t = 5 s?

a) 1. 375 m
b) 2. 300 m
c) 3. 150 m
d) 4. 75 m

Answer 1

Using the kinematic equation S = ut + ½at² with an initial velocity of 0 m/s and constant acceleration of 30 m/s², the particle's position at t = 5 s is found to be 375 meters from the starting point.

Step-by-step explanation:

To determine the particle's position at t = 5 s, we use the kinematic equation for motion with constant acceleration:

S = ut + ½at²

where:

• S is the displacement
• u is the initial velocity
• a is the constant acceleration
• t is the time

Given that the initial velocity u = 0 m/s and the constant acceleration a = 30 m/s², we can plug these values into the equation:

S = (0 m/s)(5 s) + ½(30 m/s²)(5 s)²

S = 0 + ½(30)(25)

S = ½(750)

S = 375 m

Therefore, the particle's position at t = 5 s is 375 meters from the starting point.