Question

Water towers store water above the level of consumers for times of heavy use, eliminating the need for high-speed pumps. How high above a user must the water level be to create a gauge pressure of 3.00×105N/m2?

(a) 30.0 m
(b) 5.0 m
(c) 3.0 m
(d) 0.3 m

Answer 1

To create a gauge pressure of 3.00 x 10^5 N/m², the water level must be 30.6 meters above a user.

Step-by-step explanation:

A water tower creates a gauge pressure in the water to push it out and reach the consumers without the need for high-speed pumps. To calculate the height above a user required to create a gauge pressure of 3.00×10^5 N/m², we can use the equation for pressure:

P = ρgh

where P is the pressure, ρ is the density of water, g is the acceleration due to gravity, and h is the height difference. Rearranging the equation to solve for h:

h = P / (ρg)

Since the gauge pressure and the density of water are given, we can substitute those values into the equation:

h = (3.00×10^5 N/m²) / ((1000 kg/m³)(9.8 m/s²))

Simplifying the calculation:

h = 30.6 m

Therefore, the water level must be 30.6 m above a user to create a gauge pressure of 3.00×10^5 N/m².