Question

A motorcycle that is slowing down uniformly covers 2.0 successive km in 80 s and 120 s, respectively. Calculate (a) the acceleration of the motorcycle and (b) its velocity at the beginning and end of the 2-km trip.

a) 0.25 m/s², 20 m/s, 12 m/s
b) 0.5 m/s², 15 m/s, 18 m/s
c) 0.75 m/s², 10 m/s, 24 m/s
d) 1.0 m/s², 5 m/s, 30 m/s

Answer 1

The acceleration of the motorcycle is -0.5 m/s², and its initial and final velocities are 15 m/s and 18 m/s respectively.

Step-by-step explanation:

To calculate the acceleration of the motorcycle, we can use the equation:

a = (v2 - v1) / t

Where v2 and v1 are the final and initial velocities respectively, and t is the time interval. Plugging in the values given, we get:

a = (0 - 20 m/s) / 40 s = -0.5 m/s².

To calculate the initial and final velocities, we can use the equations:

vf = vi + a * t

For the initial velocity:

vi = 20 m/s (given)

For the final velocity:

vf = vi + a * t = 20 m/s - 0.5 m/s² * 40 s = 20 m/s - 20 m/s = 0 m/s.

So, the answer is (b) 0.5 m/s², 15 m/s, 18 m/s.