Final answer:
To find the Taylor polynomial of order 3 generated by f at a = 1, we need to find the derivatives of f up to the third order evaluated at a. We can then use these derivatives to construct the polynomial.
Step-by-step explanation:
To find the Taylor polynomial of order 3 generated by f at a, we need to find the derivatives of f up to the third order evaluated at a. Then we can use these derivatives to construct the polynomial.
Given f(x) = 1/(4-x) and a = 1, let's find the derivatives:
- First derivative: f'(x) = 1/(4-x)^2
- Second derivative: f''(x) = 2/(4-x)^3
- Third derivative: f'''(x) = 6/(4-x)^4
Now, let's evaluate these derivatives at a = 1:
- First derivative at a = 1: f'(1) = 1/(4-1)^2 = 1/9
- Second derivative at a = 1: f''(1) = 2/(4-1)^3 = 2/27
- Third derivative at a = 1: f'''(1) = 6/(4-1)^4 = 6/81 = 2/27
Finally, we can use these derivatives to construct the Taylor polynomial of order 3 at a = 1:
T(x) = f(1) + f'(1)(x-1) + f''(1)(x-1)^2 + f'''(1)(x-1)^3
Substituting the values we found:
T(x) = 1/(4-1) + (1/9)(x-1) + (2/27)(x-1)^2 + (2/27)(x-1)^3
Simplifying further will give you the actual polynomial.