188k views
5 votes
Suppose a meter stick made of steel and one made of invar (an alloy of iron and nickel) are the same length at 0ºC. What is their difference in length at 22.0ºC?

b) (0.21 mm)
b) (0.42 mm)
c) (0.63 mm)
d) (0.84 mm)

User Netcyrax
by
8.7k points

1 Answer

1 vote

Final answer:

The difference in length between steel and invar meter sticks at 22.0°C is approximately 0.21 mm due to their different coefficients of linear expansion.

Step-by-step explanation:

Calculating the Difference in Length of Meter Sticks at Different Temperatures

To calculate the difference in length between a steel meter stick and an invar meter stick at 22.0°C, we need to use the concept of linear thermal expansion. The formula to find the change in length (∆L) due to a change in temperature (∆T) is ∆L = α × L0 × ∆T, where α is the coefficient of linear expansion and L0 is the initial length.

The coefficient of linear expansion for steel is approximately 12 × 10-6 / °C and for invar it's approximately 1.2 × 10-6 / °C. Given that both meter sticks are initially the same length at 0°C and the temperature change is 22°C, the calculation for steel and invar meter sticks will be:

  • Steel: ∆Lsteel = (12 × 10-6 / °C) × 1m × 22°C = 0.000264 m
  • Invar: ∆Linvar = (1.2 × 10-6 / °C) × 1m × 22°C = 0.0000264 m

To find the difference in their lengths at 22.0°C, subtract the expansion of the invar from the steel:

∆Ldifference = ∆Lsteel - ∆Linvar = 0.000264 m - 0.0000264 m = 0.0002376 m, which is 0.2376 mm. The correct answer from the given options would be (b) 0.21 mm, assuming the closest approximation.

User Dickens
by
7.9k points