Statement:
A ball is dropped from a height of 50 m.
To find out:
The velocity of the ball before touching the ground.
Solution:
- Initial velocity (u) = 0 m/s [since the ball was at rest before it was dropped]
- Height (h) = 50 m
- Acceleration due to gravity (g) = 9.8 m/s²
- Let the velocity of the ball before touching the ground be v.
- We know, the equation of motion for a freely falling body, v² = u² + 2gh.
- Putting the values in the above equation, we get
- v² = [(0)² + 2(9.8)(50)] m/s
- or, v² = 980 m²/s²
- or, v = √980 m/s
- or, v = 31.3 m/s
Answer:
The velocity of the ball before touching the ground is 31.3 m/s.
Hope you could understand.
If you have any query, feel free to ask.