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Given a (1-)*100% confidence range, what would the confidence interval be for the actual mean of a set of data is the sample mean (x), standard deviation (sigma), and sample size (N) are known?

A) x ± (z_/2 * sigma/√N)
B) x ± (z_/2 * sigma/N)
C) x ± (z_/2 * sigma * √N)
D) x ± (z_/2 * sigma)

User Wceo
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Final answer:

The confidence interval for the actual mean of a set of data, given a (1-)*100% confidence range, is x ± (z_/2 * sigma/√N).

Step-by-step explanation:

The confidence interval for the actual mean of a set of data, given a (1-)*100% confidence range, where the sample mean (x), standard deviation (sigma), and sample size (N) are known, is given by option A: x ± (z_/2 * sigma/√N).

In this formula, x represents the sample mean, sigma represents the standard deviation, and N represents the sample size. The z_/2 represents the z-score associated with the desired confidence level.

User Lodlock
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