Final answer:
To determine whether the series converges or diverges, we can use the Comparison Test with a known convergent series. By comparing the given series to a convergent series, we can show that the given series also converges.
Step-by-step explanation:
To determine whether the series ∑n=5∞ 3/(2n²−7n+5) converges or diverges, we can use the Comparison Test. First, let's compare the given series with a known convergent or divergent series.
We know that the series ∑n=1∞ 1/n2 converges, so we will compare our series to this series.
Now, we need to find a positive constant M such that 3/(2n²−7n+5) ≤ M/(n2). Since the quadratic term dominates, we can choose M=3/2, and
3/(2n²−7n+5) ≤ 3/2n2 for n ≥ 1.
Since ∑ 1/n2 converges, the given series ∑n=5∞ 3/(2n²−7n+5) also converges by the Comparison Test.