Question

Three numbers are in the ratio of 5:6:7. Find the smallest nuber if the sum is 72.

Answer 1

Answer:

20

Explanation:

Three numbers are in the ratio of 5:6:7. Find the smallest nuber if the sum is 72.

1. sum the ratios
2. divide 72 by 18 (sum of ratio)
3. multiply by 5 (smallest ratio)

• 5 + 6 + 7 = 18

• 72 : 18 =

• 4

4 × 5 = 20 (smallest number)

--------------------------------------

check

4 × 6 = 24 (number with ratio 6)

4 × 7 = 28 (biggest number)

sum

20 + 24 + 28 = 72

The answer is good