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A number,a,truncated to 1 decimal place is 7.2.A different number,n,truncated to 1 decimal place is 3.8.Write an inequality to show the lower and upper bounds of 2a+n.

User Ian Petts
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Final answer:

The inequality representing the lower and upper bounds of 2a + n, where a is truncated to 7.2 and n to 3.8, is 18.05 ≤ 2a + n < 18.35.

Step-by-step explanation:

The question involves finding the lower and upper bounds for the expression 2a + n, given that a truncated to one decimal place is 7.2 and n truncated to one decimal place is 3.8. When a number is truncated to one decimal place, the actual number could be anything up to but not including the next tenth.

Therefore, the lower bound of a is 7.15 (because it is rounded up from anything above 7.149...) and the upper bound is 7.249..., which we can consider as 7.25 for the sake of the inequality.

Similarly, for the number n, the lower bound is 3.75 and the upper bound is 3.849..., which we can also approximate as 3.85.

To find the bounds of 2a + n, we apply the bounds of a and n as follows:

  • Lower Bound: 2(7.15) + 3.75 = 14.3 + 3.75 = 18.05
  • Upper Bound: 2(7.25) + 3.85 = 14.5 + 3.85 = 18.35

Therefore, the inequality representing the lower and upper bounds of 2a + n is 18.05 ≤ 2a + n < 18.35.

User Dennis D
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