Answer:
A) 1
Explanation:
To evaluate f(1/3) = 2x + 3x ^2, plug in 1/3 for x.
f(1/3) = 2*(1/3) + 3*((1/3)^2)
Then evaluate
2(*1/3) = 2/3
(1/3)^2 = 1/9 * 3 = 1/3
1/3 + 2/3 = 1
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